2. From the top of a vertical cliff 40 m high, the object is 59.3m from the base of the cliff. Find the angle of depression to the objeci. A) 34° B ) 940 C ) 104 degrees D) 540

[tex]34^{\circ}[/tex] is the angle of depression from the vertical cliff.Option: AStep-by-step explanation:Given that, Height of the cliff (opposite side) = 40m Distance of object from the base of the cliff (adjecent side)  = 59.3m To find the angle of depression of the object. From trigonometric rule in a right angled triangle, we know that [tex]\tan \theta=\frac{\text { opposite side }}{\text { adjecent side }}[/tex] [tex]\theta=\tan -1 \frac{\text { opposite side }}{\text { adjecent side }}[/tex] Angle of depression = [tex]\tan -1 \frac{\text { height of cliff }}{\text { Distance of object from the base of the cliff }}=\tan ^{-1} \frac{40}{59.3}=34^{\circ}[/tex] Therefore, the angle of depression to the object is [tex]34^{\circ}[/tex].