MATH SOLVE

5 months ago

Q:
# WILL MARK BRAINLIEST ANSWER!Caden rolls two fair number cubes numbered from 1 to 6. He first defines the sample space, as shown below: (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6) (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6) (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6) (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6) (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6) (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6) Based on the sample space, what is the probability of getting a total of 6? (5 points) A: 7/36B: 5/36C: 8/36D: 6/36

Accepted Solution

A:

Answer:D: 6/36Step-by-step explanation:As we are given the sample space, the events that sum to 6 are:{(1,5), (2,4), (3,3),(4,2),(5,1)}Let n(S) be the number of items in sample spaen(S) = 36Let E be the event the sum is 6Then,n(E) = 6So,P(Sum of two cubes is 6) = n(E) / n(S)= 6/36So, the correct answer is: D: 6/36 ..