MATH SOLVE

2 months ago

Q:
# the dimensions of a smaller rectangle are 3ft by 9ft the dimensions of a larger rectangle are 5ft by 15ft find the ratio of the atea of the smaller rectangle to the area of the larger rectangle

Accepted Solution

A:

The ratio of the area of the smaller rectangle to the area of the larger rectangle is [tex]\frac{9}{25}[/tex]Step-by-step explanation:The formula of the area of a rectangle is A = l × w, where l and w are its dimensionsThe dimensions of a smaller rectangle are 3 ft by 9 ftThe dimensions of a larger rectangle are 5 ft by 15 ftWe want to find the ratio of the area of the smaller rectangle to the area of the larger rectangle∵ The dimensions of the smaller rectangle are 3 ft and 9 ft∴ The area of the smaller rectangle = 3 × 9 = 27 feet²∵ The dimensions of the larger rectangle are 5 ft and 15 ft∴ The area of the smaller rectangle = 5 × 15 = 75 feet²Let us find the ratio of the area of the smaller rectangle to the areaof the larger rectangle→ smaller rectangle : larger rectangle→ 27 : 75Divide the both terms of the ratio by 3→ 9 : 25The two terms of the ratio do not divisible by any other number∴ The simplest form of the ratio is 9 : 25∴ The ratio of the area of the smaller rectangle to the area of the larger rectangle = [tex]\frac{9}{25}[/tex]The ratio of the area of the smaller rectangle to the area of the larger rectangle is [tex]\frac{9}{25}[/tex]Learn more:You can learn more about the ratio in brainly.com/question/10781917#LearnwithBrainly