MATH SOLVE

2 months ago

Q:
# PLZ HELP ASAP RIGHT TRIANGLES

Accepted Solution

A:

We have two similar right angled triangles and each has the base x/2.

Using the Pythagoras theorem we can find the value of x/2 and thus the value of x. The hypotenuse is 10, perpendicular is 8 and base is x/2. So using the theorem we can write:

[tex]10^{2}=8^{2}+( \frac{x}{2})^{2} \\ \\ 100=64+ ( \frac{x}{2})^{2} \\ \\ 36=( \frac{x}{2})^{2} \\ \\ 6=( \frac{x}{2}) \\ \\ x=12[/tex]

Thus the length of side x is 12. Option C is the correct answer.

Using the Pythagoras theorem we can find the value of x/2 and thus the value of x. The hypotenuse is 10, perpendicular is 8 and base is x/2. So using the theorem we can write:

[tex]10^{2}=8^{2}+( \frac{x}{2})^{2} \\ \\ 100=64+ ( \frac{x}{2})^{2} \\ \\ 36=( \frac{x}{2})^{2} \\ \\ 6=( \frac{x}{2}) \\ \\ x=12[/tex]

Thus the length of side x is 12. Option C is the correct answer.